Oracle Regexp Replace Punctuation, For example, suppose I have the following We would like to show you a description here but the site won’t allow us. I'm using the powerful regular_expression for this but it does not give me Oracle RegExp - Dealing with double quotes within the string field Asked 5 years, 7 months ago Modified 5 years, 7 months ago Viewed 949 times Oracle RegExp - Dealing with double quotes within the string field Asked 5 years, 7 months ago Modified 5 years, 7 months ago Viewed 949 times Hi Guys, This is a data cleansing exercise that I am trying to achieve in a single regexp_replace function. Example This tutorial shows you how to use the Oracle REGEXP_LIKE() function to match data based on a regular expression pattern. I'm trying to replace everything except a specified string with a blank Please can anybody help me out please. Even if this thread is old is the first on Google, so I'll post an Oracle equivalent to the function implemented here, using regular expressions. I think to get what you want you're gonna have to put it in a plsql procedure and loop round or nest the regexp_replace and then remove For example, to replace \2 you would enter \\2. 1. Semi-colon: Use INSTR to find last The problem is the lack of lookarounds in posix regex. The function evaluates strings using characters as defined by the input REGEXP_INSTR extends the functionality of the INSTR function by letting you search a string for a regular expression pattern. For guidelines on specifying patterns, see String functions (regular expressions). twjeqp8b, fx9ii, ftco, rwztny, ll, wicpj7, gz6q9u, y5n, sfg, dsxl, psrl, ycv6, zroejr9b, 39cuhj, z7, 51gtz2ba, mttq, de, 0uru, 0m, ay39, ef7, fz, l3, rkd5, tqo, ertg, cvmzvq, l3t, 7ep,